2=98f-96f^2

Solution for 2=98f-96f^2 equation:

2=98f-96f^2

We move all terms to the left:

2-(98f-96f^2)=0

We get rid of parentheses

96f^2-98f+2=0

a = 96; b = -98; c = +2;
Δ = b2-4ac
Δ = -982-4·96·2
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-94}{2*96}=\frac{4}{192}
=1/48
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+94}{2*96}=\frac{192}{192}
=1
$